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-16x^2+215x=97
We move all terms to the left:
-16x^2+215x-(97)=0
a = -16; b = 215; c = -97;
Δ = b2-4ac
Δ = 2152-4·(-16)·(-97)
Δ = 40017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(215)-\sqrt{40017}}{2*-16}=\frac{-215-\sqrt{40017}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(215)+\sqrt{40017}}{2*-16}=\frac{-215+\sqrt{40017}}{-32} $
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